The equation of line passing through the point (2, 3, 4) and perpendicular to plane `2x+3y+z+5=0` is

The equation of the line passing through the point (3, 0, -4) and perpendicular to the plane 2x - 3y + 5z - 7 = 0 is

The equation of line passing through (2, 3, -1) and perpendicular to the plane 2x + y - 5z = 12

The equation of a line passing through the point (-1,0,3) and perpendicular to the plane 4x+3y-5z=12 are:

Find the vector equation of the line passing through the point (1,-1,2) and perpendicular to the plane 2x-y+3z-5=0

The equation of a line passing through point (1,2,3) and perpendicular to the plane x+2y-5z+9=0 are

Find the vector equation of the line passing through the point (1,-1,2) and perpendicular to the plane 2 x-y+3z-5=0.

Find the equations of the line passing through the point (-4,3,1) perpendicular to the plane x+2y-z=0 .