Home
Class 12
CHEMISTRY
The density of KCl is 1.0893 g.cm^(-) an...

The density of KCl is `1.0893 g.cm^(-)` and the length of a side of unit cell is `6.29082 Å`. The value of Avogadro's number is:

Promotional Banner

Similar Questions

Explore conceptually related problems

The density of KCl is 1.9893g cm^(-3) and the length of a side unit cell is 6.29082Å as determined by X- ray diffraction. Calculation the value of Avogadro's number.

The element chromium crystallises in a body centred cubic lattice whose density is 7.20g//cm^(3) . The length of the edge of the unit cell is 288.4 pm. Calculate Avogadro's number (Atomic mas of Cr = 52).

The element chromium crystallises in a body centred cubic lattice whose density is 7.20g//cm^(3) . The length of the edge of the unit cell is 288.4 pm. Calculate Avogadro's number (Atomic mas of Cr = 52).

The element chromium crystallises in a body centred cubic lattice whose density is 7.20g//cm^(3) . The length of the edge of the unit cell is 288.4 pm. Calculate Avogadro's number (Atomic mas of Cr = 52).

The density of KCl is 1.9893g cm ^-3 and the length of a side unit is 6.29082overset@A as determined by X-Rays diffraction. The value of Avogadro.s number calculated from these data is :

Chromium crystallizes in a body centred cubic lattice, whose density is 7.20 g//cm^3 . The length of the edge of unit cell is 288.4 pm. Calculate Avogadro's number. (Atomic mass of chromium=52)