`int_0^(pi/4)cos^2x dx`

Evaluate int_0^(pi/2) cos^2x dx

Evaluate: int_0^(pi//2)cos^2x\ dx

Evaluate the following integrals: int_0^(pi//4)|cos2x|dx

Evaluate the following integrals: int_0^(pi//4)|cos2x|dx

Prove that int_0^(pi//4) cos^2 2x sin^3 4x dx=1/6

(i) int_0^(pi/2) sin^2 x dx (ii) int_0^(pi//2) cos^2 x dx

(i) int_0^(pi//2) cos x dx (ii) int_(-pi//2)^(pi//2) cos x dx (iii) int_0^(pi//2) cos 2x dx

(i) int_0^(pi//2) sin^2 dx =pi/4 (ii) int_0^(pi//2) cos^2x dx=pi/4 (iii) int_(-pi//4)^(pi//4) sin^2 x dx=pi/4-1/2 (iv) int_(-pi//4)^(pi//4) cos^2x dx=pi/4+1/2

int_0^pi (cos^2x)dx ,