`8.sin(x/8). cos (x/2).cos (x/4).cos (x/8)`=

8sin(x/8)cos(x/2)cos(x/4)cos(x/8) is equal to

8sin.x/8.cos.x/2.cos.x/4.cos.x/8=

(sin x)/(sin x)=lambda cos(x)/(8)-cos(x)/(4)cos(x)/(2), then lambda =

intcos.(x)/(16)cos.(x)/(8)cos.(x)/(4)cos.(x)/(2)sin.(x)/(16)dx=

intcos.(x)/(16)cos.(x)/(8)cos.(x)/(4)cos.(x)/(2)sin.(x)/(16)dx=

Lim_(x to 0){"cos"((x)/(2))cos((x)/(4))cos((x)/(8))....cos((x)/(2^(n)))}=

sin ^ (8) x-cos ^ (8) x = 1

What is the value of {sin (x+y) -2 sin x+ sin(x-y)} /[cos (x-y) +cos (x+ y)-2 cos x] xx [(sin 10x- sin 8x)/ (cos-10x + cos 8x)] ? {[sin (x+y] -2 sin x+ sin(x-y)}//[cos (x-y) +cos (x+ y)-2 cos x]} xx [(sin 10x-sin 8x)//(cos10x + cos 8x)] का मान क्या है?

16 sin x cosx cos 2x cos 4x cos 8x in

If sin x+sin^(2)=1, then cos^(8)x+2cos^(6)x+cos^(4)x=