If in a conductor number density of electrons is `8.5xx10^(28)` average relaxation time 25 femtosecond mass of electron being `9.1xx10^(-31)`kg, the resistivity would be of the order.

If mass of an electron is 9.1xx10^(-31) kg, the number of electrons in 1 mg is

The mass of an electron is 9.11xx10^(-31)kg . How many elecrons would make 1kg?

Find the time of relation between collision and free path of electrons in copper at room temperature .Given resistance of copper = 1.5xx 10^(-8) Omega m number density of electron in copper = 8.5 xx 10^(28)m^(-3) charge on electron = 1.6 xx 10^(19)C , mass of electrons = 9.1 xx 10^(-19) kg Drift velocity of free electron = 1.6 xx 10^(-4)ms^(-1)

If mass of an electron is 9.11xx10^(-31) kg then how many electrons would weight in 1 mg?

Calculate the mass of 1 mol of electrons if the mass of one electron be 9.11xx10^(-31)kg .

The kinetic energy of an electron is 4.55 xx 10^(-25)J . The mass of electron is 9.1 xx 10^(-31)kg . Calculate velocity, momentum and wavelength of the electron.

The kinetic energy of an electron is 4.55 xx 10^(-25) J .The mass of electron is 9.1 xx 10^(-34) kg Calculate velocity of the electron

If the free electron density of copper is 8.6xx10^(28)m^(-3) and resistivity of copper at room temperature is 1.7xx10^(-6)Omega cm , find the relaxation time for the free electrons of copper. Given, mass of electron =9.1xx10^(-31) kg , and charge of electron =1.6xx10^(-19)C. Boltzmann's constant k = 1.38 xx 10^-23 J K^-1