An aluminium rod has a breaking strain `0.2%`. The minimum cross-sectional area of the rod in `m^(2)` in order to support a load of `10^(4)N` is fi (Young's modulus is `7xx10^(9) Nm^(-2)`)

An aluminium rod has a breaking strain 0.2%. The minimum cross-sectional area of the rod in m^2 in order to support a load of 10^4N is if Youngs modulus is 7 xx 10^9 Nm^(-2)

A metallic rod breaks when strain produced is 0.2% . The Young's modulus of the material of the rod is 7xx10^(9)N//m^(2) . What should be its area of cross-section to support a load of 10^(4)N ?

A metallic rod breaks when strain produced is 0.2% . The Young's modulus of the material of the rod is 7xx10^(9)N//m^(2) . What should be its area of cross-section to support a load of 10^(4)N ?

A uniform bar of length 2 m and cross-sectional area 50cm^(2) is subjected to a tensile load 100 N. If Young's modulus of material of bar is 2xx10^(7)N//m^(2) and poisson's ratio is 0.4, then determine the volumetric strain.

A uniform bar of length 2 m and cross-sectional area 50cm^(2) is subjected to a tensile load 100 N. If Young's modulus of material of bar is 2xx10^(7)N//m^(2) and poisson's ratio is 0.4, then determine the volumetric strain.

A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2) . It is subjected to a load of 5 kg. If Young's modulus of the material is 4 xx 10^(10) N m^(-2) , calculate the elongation produced in the wire. Take g = 10 ms^(-2)

An elongation of 0.2% in a wire of cross section 10^(-4)m^(2) causes tension 1000 N. Then its young's modulus is

A steel rod of length 5 m is fixed between two support. The coefficient of linear expansion of steel is 12.5 xx 10-6//^(@)C . Calculate the stress (in 10^(8) N//m2 ) in the rod for an increase in temperature of 40^(@)C . Young's modulus for steel is 2 xx 10^(11) Nm^(-2)