Suppose the value of the equilibrium constant for the given reaction `H_2(g) + I_(2)(g) hArr 2HI(g)` at 717 K is 64, then calculate the same (eq. const.) for the reaction `HI hArr 1/2 H_2 + 1/2 I_2`.

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The value of the equilibrium constant for the reaction H_2(g) +I_2(g) hArr 2HI(g) at 720 K is 48 . What is the value of the equilibrium constant for the reaction. 1/2 H_2(g) +1/2 I_2(g) hArr HI(g)

The value of the equilibrium constant for the reaction : H_(2) (g) +I_(2) (g) hArr 2HI (g) at 720 K is 48. What is the value of the equilibrium constant for the reaction : 1//2 H_(2)(g) + 1//2I_(2)(g) hArr HI (g)

The value of the equilibrium constant for the reaction : H_(2) (g) +I_(2) (g) hArr 2HI (g) at 720 K is 48. What is the value of the equilibrium constant for the reaction : 1//2 H_(2)(g) + 1//2I_(2)(g) hArr HI (g)

The value of equilibrium constant for the reaction H_(2)(g)+ I_(2) (g) hArr 2HI (g) is 48 at 720 K What is the value of the equilibrium constant for the reaction 2HI (g) hArr H_(2) (g) + I_(2) (g)

The value of the equilibrium constant K for the reaction H_2(g) +I_2(g) hArr 2Hl(g) " is " 48 " at " 717 K. Find out the value of K for the following reaction at Hl(g) hArr (1)/(2) H_2(g) + (1)/(2) I_2(g)

For the equilibrium reaction H_(2(g))+I_(2(g))hArr 2HI_((g))

For the equilibrium reaction H_(2(g))+I_(2(g))hArr 2HI_((g))