" (ii) "(cos(pi+theta)*cos(-theta))/(sin(pi-theta)*cos((pi)/(2)+theta))=cot^(2)theta

Prove that : (cos(pi+theta)cos(-theta))/(sin (pi-theta) cos (pi/2+ theta))= cot^2 theta.

Prove that (cos(pi+theta)cos(-theta))/(cos(pi-theta)cos((pi)/(2)+theta))=-cot theta

Prove that (cos(pi +theta)cos (-theta))/(cos(pi-theta) cos (pi/2+theta))=-cot theta

Prove that (cos (pi-theta).cot(pi/2 +theta).cos(-theta))/(tan(pi+theta).tan((3pi)/(2)+theta).sin(2pi-theta))=cos theta

If tan theta=(3)/(4) and theta is not in first quadrant sin(sin((pi)/(2)+theta)-cot(pi-theta))/(tan((3 pi)/(2)-theta)-cos((3 pi)/(2)+theta))=

Prove that: 2cos theta cos((pi)/(3)+theta)cos((pi)/(3)-theta)=cos3 theta

If tan theta = 3/4 and theta is not in the first quadrant then (sin (pi//2 + theta)-cot(pi-theta))/(tan(3 pi//2 - theta)-cos (3pi//2+theta))=

If (sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2 tan theta cot theta=-1 (AA theta in[0, 2pi], then

If (sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2 tan theta cot theta=-1 (AA theta in[0, 2pi], then