" (iui) वक्र "y^(2)(x-1)=4x^(2)," बिन्दु "(5,5)" पर "

Find the products: (i) (2x+y)(2x-y)(4x^2+y^2) (ii) (x-y/5-1)\ (x+y/5+1)

The solution of the differential equation xdy/dx+2y=x^(2),(xne0) with y(1)=1, is (a) y=x^(2)/4+3/(4x^(2)) (b) y=x^(3)/5+1/(5x^(2)) (c) y=3/4x^(2)+3/(4x^(2)) (d) y=4/5x^(3)+1/(5x^(2))

x"@"y=(x+y)^(2) x#y=(x-y)^(2) (2" @ "2)+(3#3)-(4"@"4)+(5#5) is equal to :

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))

Evaluate : (v) (4x^(2) - 5y^(2) ) (4x^(2) + 5y^(2) )

Add : 4x^(2)y, - 3xy^(2), -5xy^(2), 5x^(2)y

Find each of the following products: (i) (4x + 5y) (4x - 5y) (ii) (3x^(2) + 2y^(2)) (3x^(2) - 2y^(2))

Factorize the following polynmials: (1) x^(2)-4x-5 =x^(2)-5x+x-5 =x(x-5)+1(x-5) =(x-5)(x+1)