A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass `10^(-2)` kg moving with a speed of `2 xx 10^(2) m s^(-1)`. The height to which the bob rises before swinging back is (Take `g = 10 m s^(-2)`)

A simple pendulum of length 1m has a wooden bob of mass 1kg . It is struck by a bullet of mass 10g moving with a speed of 200m//s . The bullet gets embedded into the bob. Obtain the height to which the bob rises before swinging back. Take g=10m//s^(2) .

The wooden bob of a simple Pendulum of length 1 m is struck by a bullet of mass 10^(-3) kg moving with a speed of 300 m s^(-1) . If the bullet gets embedded into the bob then calculate the height to which the bob will rise before going back to mean position. The mass of bob is 0.8 kg .

Calculate the kinetic energy of a body of mass 2 kg moving with speed of 10 m s^(-1)

A simple pendulum of length 1 m with a bob of mass m swings with an angular amplitude 30^(@) . Then (g= 9.8m//s^(2)

A simple pendulum of length 1 m with a bob of mass m swings with an angular amplitude 30^(@) . Then (g= 9.8m//s^(2)

A wooden block of mass 0.9 kg is suspended from the ceiling of a room by thin wires. A bullet of mass 0.1 kg moving horizontally with a speed of 10 ms^(-1) strikes the block and sticks to it. What is the height to which the block rises ? Take g = 10 ms^(-2) :

A wooden bob of mass 1 kg is suspended from a string of length 1 m . It is struck by a bullet of mass 0.02 kg , moving with a speed of 300 m/s , such that the bullet gets embedded inside it . Calculate the maximum height up to which the bob will rise after the impact .