Compounds with spin only magnetic momen...

Compounds with spin only magnetic moment equivalent to five unpaired electrons are

`K_(4)[Mn(CN)_(6)]`

`[Fe(H_(2)O)_(6)]Cl_(3)`

`K_(3)[FeF(6)]`

`K_(4)[MnF_(6)]`

Text Solution

Verified by Experts

a. `K_(4)[Mn(CN)_(6)],Mn^(2+)=[Ar]3d^(5)4s^(0)`
`CN^(-)` is a strong field ligand, so pairing will take place i.e. `t_(2g)^(2,2,1) e_(g)^(0,0)`
b. `[Fe(H_(2)O)_(6)]Cl_(3),Fe^(3+)=[Ar]3d^(5)4s^(0)`
`H_(2)O` is a weak field ligand so pairing will not occur.
i.e. `t_(2g)^(1,1,1), e_(g)^(1,1)`
c. `K_(3)[FeF_(6)],Fe^(3+)=[Ar]3d^(5) 4s^(0)`
`F^(-)` is a weak field ligand, so, pairing will not occur.
i.e `t_(2g)^(1,1,1) e_(g)^(1,1)`
d. `K_(4)[MnF_(6)], Mn^(2+)=[Ar]3d^(5)4s^(0)`
`F^(-)` is a weak field ligand so, pairing will not occur.
i.e. `t_(2g)^(1,1,1)e_(g)^(1,1)`
Hence b, c and d complexes will show spin only magnetic moment equivalent to five unpaired electrons.

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A comapound in which a metal ion M^(x+)(Z=25) has a spin only magnetic moment of sqrt24 BM The number of unpaired electrons in the compound and the oxidation state of the metal ion respectively are

4 and 2

5 and 3

3and 2

4 and 3

The complex showing a spin - only magnetic moment

`[Ni(CO)_4]`

`[NiCl_4]^(2-)`

`[Ni(PPh_3)_4]`

`[Ni(CN)_4]^(2-)`

The spin only magnetic moment of Mn^(4+) ion is nearly

3BM

6BM

4BM

5BM