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0.5 mole of each H(2),SO(2) and CH(4) a...

0.5 mole of each `H_(2),SO_(2)` and `CH_(4)` are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be

A

`P_(SO_(2))gtp_(CH_(4))gtP_(H_(2))`

B

`p_(H_(2))gtP_(SO_(2))gtP_(CH_(4))`

C

`P_(CH_(4))gtP_(SO_(2))gtp_(H_(4))`

D

`P_(CH_(2))gtP_(CH_(4))gtP_(SO_(2))`

Text Solution

Verified by Experts

Initially, partial pressure were equal. As `r prop sqrt(1//d)` or `sqrt(1//m)` therefore amounts diffused out in the same time will be `H_(2)gtCH_(4)gtSO_(2)`. Amounts left will be `H_(2)gtCH_(4)ltSO_(2)` or `SO_(2)gtCH_(4)gtH_(2)`
`:.p_(SO_(2))gtp_(CH_(4))gtp_(H_(2))`
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