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The volume of 0.0168 mol of O(2) obtaine...

The volume of 0.0168 mol of `O_(2)` obtained by decomposition of `KClO_(4)` and collected by displacement of water is 428 mL at a presure of 754 mm Hg at `25^(@)C`.The pressure of water vapour at `25^(@)C`

A

18 mm Hg

B

20 mm Hg

C

22 mm Hg

D

24 mm Hg

Text Solution

Verified by Experts

Pressure of dry gas `P=nRT//V`
`=(0.0168xx0.0821xx1000xx760xx298)/428=730mm`
Pressure of moist gas =754mm
Hence pressure of water vapour `=754-730=24mm`
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