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The freezing point of water is depressed...

The freezing point of water is depressed by `0.37^@`C in a 0.01 molal NaCl solution. The freezing point of 0.02 molal solution of urea is depressed by

A

`0.37^@C`

B

`0.74^@C`

C

`0.185^(@)C`

D

`0^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
The depression in freezing point is proprtional to motal concentration of the solute ie.
`Delta T_f prop m`
`DeltaT_f = K_fmi or K_f = (DeltaT_f)/(ixxm) =` constant
so, `(DeltaT_(f_(NaCl)))/(i_(NaCl xx m_(NaCl)))=(Delta T_(furea))/(m_(Urea)xxi_(Urea))=` constant
`(0.37)/(2xx001) = (DeltaT_(fUrea))/(0.02 xx 1)rArr Delta T_(fUrea) = (0.37 xx 0.02)/(0.02) =0.37^@C`
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