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A current of 9.65 A is passed for 3 hour...

A current of 9.65 A is passed for 3 hours between nickel electrodes in 0.5 L of a 2 M solution of `Ni(NO_3)_2.` The molarity of the solution after electrolysis would be

A

0.46 M

B

0.625 M

C

0.92 M

D

1.25 M

Text Solution

Verified by Experts

The correct Answer is:
C
`Q=9.65 xx 3 xx60 xx60 = 104220 C`
`Ni^(@)+2e^(-) rarr Ni`
`2 xx 96500 C` deposit 1 mole of `Ni^(2+)`
`therefore 104220 C` will deposit `Ni^(2+)`
`(1)/(2 xx96500) xx 104220 = 0.54 ` mole
Originally 0.5 L of 2M sol. Contains `Ni^(2+)` =1 mole. Now 0.5 L will contain `Ni^(2+) =1 -0.54 =0.46` mole
Hence, molarity = 0.92 mol `L^(-1)`
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