Home
Class 12
CHEMISTRY
Lowering of vapour pressure in 1 motal a...

Lowering of vapour pressure in 1 motal aqueous solution at `100^@C` is

A

13.44 mm Hg

B

14.12 mm Hg

C

31.2 mm Hg

D

35.2 mm Hg

Text Solution

Verified by Experts

The correct Answer is:
A
Molality and mole fraction are related as follows :
`m = (x_B xx 1000)/((1-x_B)m_A), 1 = (x_B xx 1000)/((1-x_B) xx 18)`
`x_B` = mole fraction of solute, `m_A` = molar mass of solvent
`x_B` = 0.0176, `x_A` = 0.9824, p=p `x_A`
`=p 760 xx 0.9824=746.624 , Delta p = p-p= 760 -746.624`
`~~` 13.4 mm Hg
Promotional Banner

Topper's Solved these Questions

  • PHYSICAL CHEMISTRY OF SOLUTIONS

    MTG-WBJEE|Exercise WB JEE WORKOUT (One or More than One Option Correct Type )(2 mark)|10 Videos

  • PHYSICAL CHEMISTRY OF SOLUTIONS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (Single Option Correct Type)(1 Mark)|16 Videos

  • PHYSICAL CHEMISTRY OF SOLUTIONS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (Single Option Correct Type)(2 Mark)|2 Videos

  • MODEL TEST PAPTER

    MTG-WBJEE|Exercise MCQs|80 Videos

  • POLYMERS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 1 : Single Option Correct Type )|2 Videos

Similar Questions

Explore conceptually related problems

Calculate relative lowering of vapour pressure of 0.161 molal aqueous solution

Lowering of vapour pressure due to a solute in 1 molal aqueous solution at 100^(@)C is a. 13.44 mm Hg ,b. 14.14 mm Hg ,c. 13.2 mm Hg ,d. 35.2 mm Hg

Lowering of vapour pressure is highest for

The lowering of vapour pressure due to a solute in a 1 m aqueous solution at 100^(@)C is

Unit of lowering of vapour pressure is

Lowering of vapour pressure of an aqueous solution of a non-volatile non-electrolyte 1 m aqueous solution at 100^(@)C is,

The lowering of vapour pressure of 0.1 M aqueous solution NaCl, CuSO_(4) and K_(2)SO_(4) are :

The lowering of vapour pressure of 0.1 M aqueous solution NaCl, CuSO_(4) and K_(2)SO_(4) are :