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On passing a current of 1.0 ampere for 1...

On passing a current of 1.0 ampere for 16 min and 5 seconds through 1 L solution of `CuCl_(2)`, all copper of the solution was deposited at cathode. The molarity of `CuCl_2` solution was

A

0.1M

B

0.01 M

C

0.005 M

D

0.2 M

Text Solution

Verified by Experts

The correct Answer is:
C
`Cu^(2+) + 2 e rarr Cu`
`2 xx 96500 C -= 1 mol Cu=1 mol CuCl_(2)`
`Q =1 xx t =1 xx (60 xx 16 +5) = 965 C`
` therefore 965 ` C will deposit `-= (965)/(2 xx 96500)=(1)/(2000)` mole `CuCl_(2)`
`therefore` Molarity of `CuCl_(2)` solution `= (1)/(200)` mol `L^(-1)` = 0.005 M
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