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The order of equivalent conductance at i...

The order of equivalent conductance at infinite dilution for `LiCl, NaCl ` and KCl is

A

`LiCl gt NaCl gt KCl`

B

`KCl gt NaCl gt LiCl`

C

`NaCl gt KCl gt LiCl`

D

`LiCl gt KCl gt NaCl`

Text Solution

Verified by Experts

The correct Answer is:
B
`Li^(+)` ,due to its high polarising power gets hydrated and its ionic mobility is reduced. Smallar the cation, higher is the hydration enthalpy and heavier becomes the cation. Mobility and conductance decrease.
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The correct order of equivalent conductance at infinite dilution of LiCl, NaCl and KCl is:

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation : kappa=c xx l/A where, c=1//R is the conductance and l//A is the cell constant. Molar conductance (Lambda_(m)) and equivalence conductance (Lambda_(e)) of an electrolyte solution are calculated using the following similar relations : Lambda_(m)= kappa xx 1000/M Lambda_(e)= kappa xx 1000/N Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : Lambda_(m)=Lambda_(m)^(@)-b sqrt(c) where, Lambda_(m)^(@)= molar conductance at infinite dilution c= concentration of the solution b= constant The degrees of dissociation of weak electrolytes are calculated as : alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@) The correct order of equivalent conductances at infinite dilution of LiCl, NaCl and KCl is :

The correct order of molar conductivity at infinite dilution of LiCl, NaCl and KCl is

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