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The solubility product of silver chromat...

The solubility product of silver chromate be `K_(sp)`, its solubility is

A

`root(3)(K_(sp ) //8)`

B

`root(3)(K_(sp))`

C

`root(3)(K_(sp)//4)`

D

`root(3)(K_(sp) //2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Ag_2 CrO _4 ` dissociates as
`Ag_2 CrO_4 hArr 2Ag^+ +CRO_(4)^(-)`
`K_(sp) =[Ag^+] ^2 [CrO_(4)^(-)]`
suppose the solubilty of ` Ag_2 CrO_4` is S mol /litre then
`K_(sp ) = (2s)^2 (s ) = 4s^3`
` therefore S= root(3) (K_(sp ) //4)`
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