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The ratio of volumes of CH3 COOH 0.1 (N)...

The ratio of volumes of `CH_3 COOH `0.1 (N) to `CH_3 COONa 0.1 `(N) required to prepare a buffer solution of pH 5.74 is (given : `pK_a ` of `CH_3 COOH `is 4.74)

A

`10 :1`

B

`5 :1`

C

`1 :5`

D

`1 :10`

Text Solution

Verified by Experts

The correct Answer is:
D
`pH = pK_a +log _(10) ("Activity of salt ")/("activity of acid ")`
` 5.74 =4.74 + log_(10) "concentration " xx " Volume "_(("salt"))/( "concentration " xx" volume"_("acid"))`
[Concentration given are same ]
` 1= log _(10) (v_("salt"))/( V_("acid ")) implies V_("salt ") : V_("acid") = 10 :1 `
` therefore V_("acid") :V_("salt")= 1: 10`
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