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n small drops of same size are charged t...

`n` small drops of same size are charged to `V` volts each .If they coalesce to from a single large drop, then its potential will be -

A

`V//n`

B

Vn

C

`Vn^(1//3)`

D

`V_(n)^(2//3)`

Text Solution

Verified by Experts

The correct Answer is:
d
`n(4)/(3)pir^(3)=(4)/(3)piR^(3)rArrR=n^(1//3)rV=(q)/(4piepsilon_(0))r`
and `V.-(nq)/(4piepsilon_(0)R)rArrV.(nq)/(4piepsilon_(0)n^(1//3)r)thereforeV.=n^(2//3)V`
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