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If 3 charges are placed at the vertices ...

If `3` charges are placed at the vertices of equilateral triangle of charge 'q' each. What is the net potential energy, if the side of equilateral `Delta` is `l cm` ?

A

`(1)/(4piepsilon_(0))(q^(2))/(l)`

B

`(1)/(4piepsilon_(0))(2q^(2))/(l)`

C

`(1)/(4piepsilon_(0))(3q^(2))/(l)`

D

`(1)/(4piepsilon_(0))(4q^(2))/(l)`

Text Solution

Verified by Experts

The correct Answer is:
c
P.E . Between any two charges,
`U=(1)/(4piepsilon_(0))(q_(1)q_(2))/(r)`
Here we have to consider three pairs wherein
`q_(1)=q_(2)=andr=l` for all pairs.
Net potential energy `=3xx(qxxq)/(4piepsilon_(0)l)=(1)/(4piepsilon_(0))(3q^(2))/(l)`
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