A parallel plate capacitor is charged and the charging battery is then disconnected. If the plates of the capacitor are moved farther apart by means of insulating handles:

Options

A. the energy stored in the capacitor decreases
B. the capacitance of the capacitor increases
C. the charge on the capacitor decreases
D. the voltage across the capacitor increases

Answer

d

Explanation

Charging battery is removed.
`therefore` Q = constant.
Distance between the plates is increased.
`therefore` C decreases. `(becauseC=(epsilon_(0)A)/(d))`
Now , `V=(Q)/(C)`, Q is constant and C is decreasing.
`therefore` V increases.
`U=(1)/(2)(Q^(2))/(C)` again Q is constant and C is decreasing.
`therefore` U increases.