A `5muF` capacitor is connected in series with a `10muF` capacitor. When a 300 volt potential difference is applied across this combination, the total energy stored in the capacitors is

Options

A. 15 J
B. `1.5 J`
C. `0.15 J`
D. `010 J`

Answer

c

Explanation

Here , `C_(1)=5muF`
`C_(2)=10muF`
`V=300V`
U=?
Equivalent capacitance of the circuit,
`C=(C_(1)xxC_(2))/(C_(1)+C_(2))=(5xx10)/(5+10)=(10)/(3)muF=(10)/(3)xx10^(-6)F`
`U=(1)/(2)CV^(2)=(1)/(2)xx(10)/(3)xx10^(-6)xx(300)^(2)=0.15J`