A hollow metal sphere of radius R is charged with a charge Q. The electric potential and intensity inside the sphere are respectively

Options

A. `(Q)/(4piepsilon_(0)R^(2))and(Q)/(4piepsilon_(0)R)`
B. `(Q)/(4piepsilon_(0)R)andZero`
C. Zero and Zero
D. `(4piepsilon_(0)Q)/(R)and(Q)/(4piepsilon_(0)R^(2))`

Answer

b

Explanation

Electric field :
Using Gauss .s law ,
`ointvecE.dvecs=0`
`E.4pir^(2)=0`
E=0
Now ,`E=-(dV)/(dr)rArr(dV)/(dr)=0rArrV=` constant
`V=(Q)/(4piepsilon_(0)R)`