Three capacitors of capacitacnce 1.0, 2.0 and `5.0muF` are connected in series to a 10 V source. The potential difference across the `2.0muF` capacitor is

Options

A. `(100)/(17)V`
B. `(20)/(17)V`
C. `(50)/(17)V`
D. 10 V

Answer

c

Explanation

The capacitors are connected in series , then total capacitance is given by ,
`(1)/(C)=(1)/(1)+(1)/(2)+(1)/(5)rArrC=(10)/(17)muF`
Now , total charge `Q=CV=(10)/(17)muFxx10V=(100)/(17)muF`
Potential difference across the `2muF` capacitor,
`V=(Q)/(C)=(100)/(17xx2)V=(50)/(17)V`