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Angle between the pair of straight lines...

Angle between the pair of straight lines `x^(2) - xy - 6y^(2) - 2x + 11y - 3 = 0` is

A

`45^(@), 135^(@)`

B

`tan^(-1) 2, pi - tan^(-1) 2`

C

`tan^(-1) 3, pi - tan^(-1) 3`

D

None of these

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AI Generated Solution

The correct Answer is:
To find the angle between the pair of straight lines given by the equation \(x^2 - xy - 6y^2 - 2x + 11y - 3 = 0\), we can follow these steps: ### Step 1: Identify the coefficients The general form of the equation of a pair of straight lines is given by: \[ ax^2 + by^2 + 2hxy + 2gx + 2fy + c = 0 \] From the given equation, we can identify the coefficients: - \(a = 1\) (coefficient of \(x^2\)) - \(b = -6\) (coefficient of \(y^2\)) - \(h = -\frac{1}{2}\) (coefficient of \(xy\) is \(-1\), so \(2h = -1\) implies \(h = -\frac{1}{2}\)) - \(g = -1\) (coefficient of \(x\) is \(-2\), so \(2g = -2\) implies \(g = -1\)) - \(f = \frac{11}{2}\) (coefficient of \(y\) is \(11\), so \(2f = 11\) implies \(f = \frac{11}{2}\)) - \(c = -3\) ### Step 2: Use the formula for the angle between the lines The formula for the tangent of the angle \(\theta\) between the pair of straight lines is given by: \[ \tan \theta = \left| \frac{2\sqrt{h^2 - ab}}{a + b} \right| \] ### Step 3: Calculate \(h^2 - ab\) Now we need to calculate \(h^2 - ab\): \[ h^2 = \left(-\frac{1}{2}\right)^2 = \frac{1}{4} \] \[ ab = 1 \cdot (-6) = -6 \] \[ h^2 - ab = \frac{1}{4} - (-6) = \frac{1}{4} + 6 = \frac{1}{4} + \frac{24}{4} = \frac{25}{4} \] ### Step 4: Calculate \(a + b\) Now calculate \(a + b\): \[ a + b = 1 - 6 = -5 \] ### Step 5: Substitute into the formula Now substitute \(h^2 - ab\) and \(a + b\) into the formula for \(\tan \theta\): \[ \tan \theta = \left| \frac{2\sqrt{\frac{25}{4}}}{-5} \right| = \left| \frac{2 \cdot \frac{5}{2}}{-5} \right| = \left| \frac{5}{-5} \right| = 1 \] ### Step 6: Determine the angle \(\theta\) Since \(\tan \theta = 1\), we have: \[ \theta = 45^\circ \text{ or } 225^\circ \] The angle between the lines is typically taken as the acute angle, so: \[ \theta = 45^\circ \] ### Final Answer The angle between the pair of straight lines is \(45^\circ\).
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