सरल करें:
`[(1+1/(10+1/10))xx(1+1/(10+1/10))-(1-1/(10+1/10))xx(1-1/(10+1/10))]-:[(1+1/(10+1/10))+(1-1/(10+1/10))]`

[(1+(1)/(10+(1)/(10)))xx(1+(1)/(10+(1)/(10)))-(1-(1)/(10+(1)/(10)))xx (1-(1)/(10+(1)/(10)))+(1+(1)/(10+(1)/(10)))+(1-(1)/(10+(1)/(10)))] simplifies to

1. (1)/(10)+(3)/(10)+(6)/(10)

[(1+(1)/(10+(1)/(10)))(1+(1)/(10+(1)/(10)))-(1-(1)/(10+(1)/(10)))(1-(1)/(10+(1)/(10)))] simplifies to (20)/(101) (b) (90)/(101) (c) (100)/(101) (d) (101)/(100)

10 div 10 xx 10 + 10 - 1

(1/4)^(-10)xx(2/5)^(-10)

1/4+2/4 3/10+2/10+1/10

((1)/(1xx4)+(1)/(4xx7)+(1)/(7xx10)+(1)/(10xx13)+(1)/(13xx16))=?

Is [(-10)xx1)]xx3=(-10)xx[(1xx3)] ?

((1)/(1.4 )+ (1)/(4.7 ) +(1)/(7.10 )+(1)/(10.13 )+(1)/(13.16)) is equal to