Let B and C are points of interection of the parabola `y=x^(2)` and the circle `x^(2)+(y-2)^(2)=8.` The area of the triangle OBC, where O is the origin, is

Let B and C are the points of intersection of the parabola x=y^(2) and the circle y^(2)+(x-2)^(2)=8 . The perimeter (in units) of the triangle OBC, where O is the origin, is

Let B and C are the points of intersection of the parabola x=y^(2) and the circle y^(2)+(x-2)^(2)=8 . The perimeter (in units) of the triangle OBC, where O is the origin, is

P and Q are the points of intersection of the curves y^(2)=4x and x^(2)+y^(2)=12 . If Delta represents the area of the triangle OPQ, O being the origin, then Delta is equal to (sqrt(2)=1.41) .

The point of intersetion of the tangents to the parabola y^(2)=4x at the points where the circle (x-3)^(2)+y^(2)=9 meets the parabola, other than the origin,is

Two tangents to the circle x^(2)+y^(2)=4 at the points A and B meet at M(-4, 0). The area of the quadrilateral MAOB, where O is the origin is

Two tangents to the circle x^2 +y^2=4 at the points A and B meet at P(-4,0) , The area of the quadrilateral PAOB , where O is the origin, is

Two tangents to the circle x^(2)+y^(2)=4 at the points A and B meet at P(-4,0), The area of the quadrilateral PAOB, where O is the origin,is

Let A(4,-4) and B(9,6) be points on the parabola y^(2)=4x. Let C be chosen on the on the arc AOB of the parabola where O is the origin such that the area of DeltaACB is maximum. Then the area (in sq. units) of DeltaACB is :

Let A(4,-4) and B(9,6) be points on the parabola y^(2)=4x. Let C be chosen on the on the arc AOB of the parabola where O is the origin such that the area of DeltaACB is maximum. Then the area (in sq. units) of DeltaACB is :

Let A(4,-4) and B(9,6) be points on the parabola y^(2)=4x. Let C be chosen on the on the arc AOB of the parabola where O is the origin such that the area of DeltaACB is maximum. Then the area (in sq. units) of DeltaACB is :