Home
Class 11
PHYSICS
By the method of dimensions, test the ac...

By the method of dimensions, test the accuracy of the equation : `delta = (mgl^3)/(4bd^3Y)` where `delta` is depression in the middle of a bar of length I, breadth b, depth d, when it is loaded in the middle with mass m. Y is Young's modulus of meterial of the bar.

Promotional Banner

Similar Questions

Explore conceptually related problems

If delta is the depression produced in a beam of length L, breadth b and thickness d, when a load is placed at the mid point, then

Let a steel bar of length l, breadth b and depth d be laoded at the centre by a load W. Then the sag of bending of beam is (Y = young's modulus of material of steel)

Let a steel bar of length 'l', breadth 'b' and depth 'd' be loaded at the centre by a load 'W'. Then the sag of bending of beam is (Y=Young's modulus of material of steel)

Let a steel bar of length 'l', breadth 'b' and depth 'd' be loaded at the centre by a load 'W'. Then the sag of bending of beam is (Y=Young's modulus of material of steel)

Let a steel bar of length 'l', breadth 'b' and depth 'd' be loaded at the centre by a load 'W'. Then the sag of bending of beam is (Y = Young's modulus of material of steel)

Let a steel bar of length 'l', breadth 'b' and depth 'd' be loaded at the centre by a load 'W'. Then the sag of bending of beam is (Y = Young's modulus of material of steel)

Find the dimensions of the quantity q from the expression : T = 2pi sqrt((ml^3q)/(5Y)), Where T is tiem period of a bar of length I, mass m and Young's modulus Y.

The increase in energy of a metal bar of length L and cross-sectional area A when compressed with a load M along its length is (where, Y= Young's modulus of the material of metal bar)

The increase in energy of a metal bar of length L and cross-sectional area A when compressed with a load M along its length is (where, Y= Young's modulus of the material of metal bar)