[" 16.The "1.6" of "x(1-x^(2))dy=(2x^(2)y-y-ax^(3))dx],[e^(" Jed "x)" then "P=?]

(x-x^(3))(dy)/(dx)+(2x^(2)-1)y=ax^(3)

If integrating factor of x(1-x^(2))dy+(2x^(2)y-y-ax^(3))dx=0 is e^(int pdx, then P is equal to )

If the integrating factor of x(1-x^(2)) dy + 2(x^(2)y-y-ax^(3)) dx =0 is e^(int p dx) where P is equal to (kx^(2)-1)/(x(1-x^(2)) then what will be the value of k ?

The solution of 3x(1-x^(2))y^(2)(dy)/(dx)+(2x^(2)-1)y^(3)=ax^(3) is

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(dy)/(dx)+(1)/(2x)y=(x)/(y^(3))

(y-x(dy)/(dx))=3(1-x^(2)(dy)/(dx))