समीकाण `E^0 = ("RT")/("nF")"InK"_(c)` कहलाता है ---

The equation, E^@ =(RT)/(nF)In K_c is called :

The questions consist of two atatements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses : E_("cell")^@ =0 for a chloride ion concentration cell . For this concentration cell where E_("cell") = ("RT")/("nF") In ([Cl^-]_(LHS))/([Cl^-]_(RHS)) .

Nernst equation is E = E^(@)-(RT)/(nF)lnQ . If Q = K_(C) , then which one is one correct,

The Nernst equation , E = E^(0) -(RT)/(nF) . In Q indicates that the equilibrium constant K_(c) will be equal to Q when :

Write the Nernst equation for the electrode reaction. M^(n+) ( aq) + n e^(-) rarr M(s) E = E^(@) - ( 2.303 RT )/( nF ) log""( [ M ] )/([ M ^(n+)])

Nernst equation gives the variation of potential of an electrode based on activity of ions temperature and pressure. The equation is E=E^(@) -(2.303RT)/(nF) logQ (or) E=E^@ - (0.0591)/(n) log Q E^@ = Standard potential and 'Q' is the reaction quotient. Which cell has least potential ?

Nernst equation for the reaction aA+bBoverset("ne"-)rarr cC+ dD is E_(cell)=E_(cell)^(@)-(RT)/(nF) "ln" Q what is Q in the Nernst equation