`2 log_(4) (4 - x) = 4 - log_(2) ( - 2 - x)`.

2log_(4)(4-x)=4-log_(2)(-2-x)

Solve : log_2 (4-x) = 4 - log_2 (-2-x)

Solve : log_(2)(4-x)=4-log_(2)(-2-x)

Solve the following equations for 'x' : 2log_4 (4-x)=4-log_2(-2-x)

If log_(4)(log_(2)x) + log_(2) (log_(4) x) = 2 , then find log_(x)4 .

If x gt 0, and log_(2) + log_(2)(sqrt(x)) + log_(2) (4sqrt(x)) + log_(2) ( 8sqrt(x)) + log_(2) (16sqrt(x)) + ….. = 4 then x =

The equation : x^(3//4 (log_(2) x)_(4)^(2) + log_(2) x - 5//4) = sqrt(2) has :

If "log"_(4) 2 + "log"_(4) 4 + "log"_(4) 16 + "log"_(4) x = 6 , then x =

If "log"_(4) 2 + "log"_(4) 4 + "log"_(4) 16 + "log"_(4) x = 6 , then x =