Acceleration of a particle moving along the x-axis is defined by the law `a=-4x`, where a is in `m//s^(2)` and x is in meters. At the instant `t=0`, the particle passes the origin with a velocity of `2 m//s` moving in the positive x-direction.
(a) Find its velocity v as function of its position coordinates.
(b) find its position x as function of time t.
(c) Find the maximum distance it can go away from the origin.

Acceleration of particle moving along the x-axis varies according to the law a=-2v , where a is in m//s^(2) and v is in m//s . At the instant t=0 , the particle passes the origin with a velocity of 2 m//s moving in the positive x-direction. (a) Find its velocity v as function of time t. (b) Find its position x as function of time t. (c) Find its velocity v as function of its position coordinates. (d) find the maximum distance it can go away from the origin. (e) Will it reach the above-mentioned maximum distance?

Acceleration of particle moving along the x-axis varies according to the law a=-2v , where a is in m//s^(2) and v is in m//s . At the instant t=0 , the particle passes the origin with a velocity of 2 m//s moving in the positive x-direction. (a) Find its velocity v as function of time t. (b) Find its position x as function of time t. (c) Find its velocity v as function of its position coordinates. (d) find the maximum distance it can go away from the origin. (e) Will it reach the above-mentioned maximum distance?

Acceleration of particle moving along the x-axis varies according to the law a=-2v , where a is in m//s^(2) and v is in m//s . At the instant t=0 , the particle passes the origin with a velocity of 2 m//s moving in the positive x-direction. (a) Find its velocity v as function of time t. (b) Find its position x as function of time t. (c) Find its velocity v as function of its position coordinates. (d) find the maximum distance it can go away from the origin. (e) Will it reach the above-mentioned maximum distance?

A particle is moving along the x-axis with an acceleration a = 2x where a is in ms^(–2) and x is in metre. If the particle starts from rest at x=1 m, find its velocity when it reaches the position x = 3.

A particle is moving along the x-axis with an acceleration a = 2x where a is in ms^(–2) and x is in metre. If the particle starts from rest at x=1 m, find its velocity when it reaches the position x = 3.

The acceleration of a particle moving in straight line is defined by the relation a= -4x(-1+(1)/(4)x^(2)) , where a is acceleration in m//s^(2) and x is position in meter. If velocity v = 17 m//s when x = 0 , then the velocity of the particle when x = 4 meter is :

The acceleration of a particle moving in straight line is defined by the relation a= -4x(-1+(1)/(4)x^(2)) , where a is acceleration in m//s^(2) and x is position in meter. If velocity v = 17 m//s when x = 0 , then the velocity of the particle when x = 4 meter is :

The velocity of a particle moving on the x-axis is given by v=x^(2)+x , where x is in m and v in m/s. What is its position (in m) when its acceleration is 30m//s^(2) .

The velocity of a particle moving on the x-axis is given by v=x^(2)+x , where x is in m and v in m/s. What is its position (in m) when its acceleration is 30m//s^(2) .

The acceleration of a particle moving along x-direction is given by equation a=(3-2t) m//s^(2) . At the instant t=0 and t=6 s , it occupies the same position. (a) Find the initial velocity v_(o) (b) What will be the velocity at t=2 s ?