If `tan40^o =lambda`, then`(tan140^o -tan130^o )/(1+tan140^o tan130^o)`=

If tan 40^(@) = lambda , then (tan 140^(@) - tan 130^(@))/(1 + tan 140^(@) tan 130^(@)) =

If tan 40^(@)= lambda , then (tan 140^(@)-tan 130^(@))/(1+ tan 140^(@) tan 130^(@))=

If tan20=lambda ,prove that (tan160^(@)-tan110^(@))/(1+tan160^(@)*tan110^(@))=(1-lambda^(2))/(2 lambda) .

If tan20^(@) = lambda then show that (tan 160^(@) -tan 110^(@))/(1+tan160^(@).tan110^(@)) = (1-lambda^2)/(2lambda) .

(i) If tan 20^(@) = lambda then show that (tan 610^(@) + tan 700^(@))/(tan 560^(@) - tan 470^(@))=(1-lambda^(2))/(1+lambda^(2))

tan40^(@)+tan80^(@)-sqrt(3)tan40^(@)tan80^(@)=

tan20^(@)tan30^(@)tan40^(@)tan80^(@)=1