To lift an automobile of 2000 kg, a hydraulic pump with a large piston 30 cm square in area is employed. Calculate the force that must be applied to pump a small piston of area 10 square cm to achieve it.

To lift an automobile of 200 kg. a hydraulic pump with a larger piston 900cm^(2) in area is employed. Calculate the force that must be applied to pump a small piston of area 10cm^(2) to accomplish this task.

The diameters of the larger and the smaller pistons of a hydraulic press are 45 cm and 5 cm respectively. Find the magnitude of the force that has to be applied on the smaller piston to produce a 4050 N thrust on the larger piston.

In a hydraulic lift the radius of small piston is 5.0 cm and that of larger piston is 15cm . Calculate the force F, if the mass of the car to be lifted is 1350 kg ( g=9.8 ms^-2 )

A car of mass 1400 kg placed on the platform in a service station has to be lifted up. The area of the press piston to which the platform is 5m^(2) . Determine the force that has to be applied on the piston of pump cylinder having an area of cross section 0*25m^(2) . (Take g = 10 m s^(-2))

Two piston of a hydraulic lift have diameters of 60 cm and 5 cm. What is the force exerted by the larger piston when 50 N is placed on the smaller piston ?

The area of smaller piston of a hydraulic pressure is 2cm square and that of larger piston is 20 cm square. How much weight can be raised on the larger piston when a force 200kg f is exerted on the smaller piston? g=10m//s^(2)

In a hydraulic machine, a force of 2 N is applied on the piston of area of cross section 10 "cm"^2 . What force is obtained on its piston of area of cross section 100 "cm"^2 ?

A hydraulic lift is designed to lift a maximum, mass of 3000 kg and area of the piston carrying it is 425 cm^(2) . What is the maximum pressure \that should be applied to the smaller piston?