For equilibrium `H_(2)+I_(2) hArr 2HI` which of the following will affect the equilibrium constant ?

H_(2)+I_(2) hArr2HI Which one of the following will not affect the rate of this reaction ?

For a reaction : H_(2) (g) + I_(2) (g) hArr 2HI (g) at 721 K, the value of the equilibrium constant is 50. If 0.5 mole each of H_(2) " and "I_(2) are added to the system the value of the equilibrium constant will be :

The equilibrium constant, K_(c ) for the reaction : H_(2)+I_(2) hArr 2HI at 700 K is 49. What is the equilibrium constant for the reaction : HI hArr (1)/(2)H_(2)+(1)/(2)I_(2) at the same temperature ?

The value of equilibrium constant for the reaction H_(2)(g)+ I_(2) (g) hArr 2HI (g) is 48 at 720 K What is the value of the equilibrium constant for the reaction 2HI (g) hArr H_(2) (g) + I_(2) (g)

The equilibrium constant of the reaction H_2(g) + I_2(g) harr 2HI(g) is 57 at 700 K. Now, give the equilibrium constants for the following reaction at the same temperature: 4HI(g) harr 2H_2(g) +2I_2(g)

If the equilibrium constant for the reaction, H_(2)(g) +I_(2)(g) hArr 2HI(g) is K What is the equilibrium constant of HI(g) rarr 1/2 H_(2)(g) + 1/2I_(2)(g) ?

The equilibrium H_(2(g)) + I_(2(g)) hArr 2HI_(g) is not affected by the change in _______.

The value of the equilibrium constant for the reaction : H_(2) (g) +I_(2) (g) hArr 2HI (g) at 720 K is 48. What is the value of the equilibrium constant for the reaction : 1//2 H_(2)(g) + 1//2I_(2)(g) hArr HI (g)