For a gas undergoing an adiabatic change, the relation between temperature and volume is found to be `TV^(0.4)` = constant. This gas must be

For a gas undergoing an adiabatic process, the relation between temperature and volume is found to be TV^(@.4) = constant. The gas may be

For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume TV^(x) = constant, where x is

For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume TV^(x) = constant, where x is

An ideal gas undergoing adiabatic expansion obeys the relations

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature .The relation between temperature and volume for this process in TV^x = constant ,then x is :

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature .The relation between temperature and volume for this process in TV^x = constant ,then x is :

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature .The relation between temperature and volume for this process in TV^x = constant ,then x is :

Explain the relation between temperature and volume of gas- when the pressure is kept constant.