Home
Class 12
CHEMISTRY
[Cu(NH3)4]^(2+) is square planar, where...

`[Cu(NH_3)_4]^(2+)` is square planar, where as `[NiCl_(4)]^(2-)` is tetrahedral. Explain.

Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS AND BIO-COORDINATION COMPOUNDS

    NCERT BANGLISH|Exercise SELF EVALUATION (B. Answer in one or two sentences)|10 Videos

  • CHEMISTRY IN ACTION

    NCERT BANGLISH|Exercise SELF EVALUATION((C) Answer not exceeding sixty words :)|2 Videos

  • D-BlOCK ELEMENTS

    NCERT BANGLISH|Exercise SELF EVALUATION (ANSWER IN ONE OR TWO SENTENCES)|16 Videos

Similar Questions

Explore conceptually related problems

[Cr(NH_(3))_(6)]^(3+) is paramagnetic while [Ni(CN)_(4)]^(2-) is diamagnetic. Explain why?

Explain on the basis of valence bond theory that [Ni(CN)_(4)]^(2-) ion with square planar structure is diamagnetic and the [NiCl_(4)]^(2-) ion with tetrahedral geometry is paramagnetic.

[Ni(NH)_(4)]^(2-) is diamagnetic but [NiCl_(4)]^(2-) is paramagnetic. Give the hybridisation of Ni^(2+) in the given complex ions.

K_(2)[PtCl_(6)] is a well known compound whereas K_(2)[NiCl_(6)] is not known. Explain.

BH_(4)^(-) and NH_(4)^(-) ions are isolobal - explain.

Explain why [Cu(NH_(3))_(4)]^(2+) is coloured but [Cu(CN)_(4)]^(3-) is colourless.

Magnetic moment (spin only) of [NiCl_(4)]^(2-) -

[NiCl_(4)]^(2-) is paramagnetic while [Ni(CO)_(4)] is diamagnetic though both are tetrahedral. Why?

BCl_3 is planar while NH_3 is pyramidal. Explain.

How many unpaired electrons are there in [Pt(CN)_(4)]^(2-) ion (square planar)?