Home
Class 12
CHEMISTRY
On neutron bombardment fragmentation of ...

On neutron bombardment fragmentation of U-235 occurs according to the equation.
`92^(U^(235)) + 0^(n^(1)) rarr 42^(Mo^(98)) + 54^(Xe^(136)) + ^x(-1)^(e^(0))` + y `0^(n^(1))` Calculate the values of x and y.

Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    NCERT BANGLISH|Exercise SELF EVALUATION|31 Videos
  • NUCLEAR CHEMISTRY

    NCERT BANGLISH|Exercise SELF EVALUATION|31 Videos
  • ISOMERISM IN ORGANIC CHEMISTRY

    NCERT BANGLISH|Exercise SELF EVALUATION (CONFORMATION(Short answer questions.))|2 Videos
  • ORGANIC NITROGEN COMPOUNDS

    NCERT BANGLISH|Exercise Diazonium chloride|4 Videos

Similar Questions

Explore conceptually related problems

On neutron bombardment fragmentation of U-235 occurs according to the equation 92^(U^(235)) + 0^(n^(1)) rarr 42^(Mo^(95)) + 57^(La^(139)) + x_(-1)^(e^(0)) + y_(0)^(n^(1)) Calculate the values of x and y.

IF y=e^(msin^-1x) , find the value of (y_2)_0 .

Solve ( 1+e^(x).y) dx + xe^(x) dy = 0

If y=(1+x)(1+x^(2))(1+x^(4))…(1+x^(2n)) then the value of ((dy)/(dx)) at x = 0 is

If y=(1+x)(1+x^(2))(1+x^(4))…..(1+x^(2n)) then the value of ((dy)/(dx)) at x = 0 is

2x +(y-1)/3=0 in this equation replace y by x and find value of x and y.

92^(U^(235)) nucleus absorbs a neutron and disintegrates into 54^(Xe^(139)), 38^(Sr^(94)) and x. What will be the product x?

Solve the differential equation: (1+y^2)+(x - e^(tan^-1 y) )dy/dx = 0

Complete the following nuclear equations : ._92U^235 + ._0n^1 to ._56Ba^141 + ._36Kr^92 + ___ ._0n^1

The product P of the nuclear reaction ""_(92)^(235)U+""_(0)^(1)n to P +""_(36)^(92)Kr +3""_(0)^(1)n is