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If 50 milli ampere of current is passed ...

If 50 milli ampere of current is passed through copper coulometer for 60 min, calculate the amount of copper deposited.

Text Solution

Verified by Experts

Electrical charge input `=Ixx"t coulombs"`
`=50xx10^(-3)Axx60xx60sec`
`="180 coulombs."`
The chemical reaction is, `Cu^(2+)+2e rarr Cu_((s))`
1 gm atom of copper requires 2F current
`therefore" amount of copper deposted "=(63.5g.mol^(-1)xx180C)/(2xx96500C)`
`=0.0592gm.`
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