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Calculate the pH of "0.001 M HCl" soluti...

Calculate the pH of `"0.001 M HCl"` solution

Text Solution

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`pH+pOH=14.0" "therefore pOH=14.0-pH`
`=14.0-5.5=8.50`
`pOH=8.5" "therefore" antilog "[-pOH]`
`therefore[OH^(-)]="antilog "[-8.5]=3.2xx10^(-9)M`
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