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How emf of a cell is determined ?...

How emf of a cell is determined ?

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Emf of each of 15 cells is 2V and internal resistance of each is 0.1 Omega . The cells are arranged in a parallel combination containing 3 rows of 5 cells each. Determine the emf and internal resistance of the entire combination of cells.

A battery of steady emf 2.0 V is connected across the two ends of a potentiometer wire . With the help of this arrangement , the emf of more than …. V of a cell can not be determined . (Fill in the blank )

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In a potentimeter arrangment for determining the emf of a cell , the balance point of the cel in open circuit is 350 cm . When a resistance of 9Omega is used in the external circuit of h the balance point shift to 300cm . Determine the internal reistance of the cell .

With the help of a potentiometer , the emf of a cell can be measured accurately , because in this experiment ………of the cell becomes zero . (fill in the blank)

Show that in a closed circuit the potential difference between the two ends of a cell is less than the emf of that cell.

A few storage cells in series are to be charged from a 200 V dc supply. The emf of each cell is 2.5 V, Internal resistance 0.1 Omega and the charging current is 8A. In this arrangement how many cells can be charged and what extra resistance is required to be conncted in the circuit?

For a cell reaction involving two electron changes the standard emf of the cell is found to be 0.295V at 25C. The equilibrinm constant of the reaction at 25^@C will be?