Home
Class 12
CHEMISTRY
The emf of the cell : Cd//CdCl(2).25H(2)...

The emf of the cell : `Cd//CdCl_(2).25H_(2)O //AgCl_((s))Ag` is 0.675V. Calculate `DeltaG` of the cell reaction.

Text Solution

Verified by Experts

`n=2, DeltaG=-130.335kJ`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY - II

    NCERT BANGLISH|Exercise SELF EVALUATION((C) Answer not exceeding sixty words :)|2 Videos
  • ELECTRO CHEMISTRY - I

    NCERT BANGLISH|Exercise SELF EVALUATION((D) Solve the problems :)|8 Videos
  • ETHERS

    NCERT BANGLISH|Exercise SELF EVALUATION ((D) Answer not exceeding sixty words :)|7 Videos

Similar Questions

Explore conceptually related problems

Write the cell reaction for the half cell Cl_((aq))^-)//AgCl_((s))Ag.

The standard potential of the following cell is 0.23 V at 15^(@)C and 0.21 V" at "35^(@)C: Pt|H_(2)(g)|HCl(aq)|AgCl(s)|Ag(s) (2) Calculate DeltaH^(@) andDeltaS^(@) for the cell reaction by assuming that these quantities remain unchanged in the range 15^(@)C" to "35^(@)C .

The emf of the half cell Cu_((aq))^(2+)//Cu_((s)) containing "0.01 M Cu"^(2+) solution is +0.301 V . Calculate the standard emf of the half cell.

For the cell, Zn|ZnO_(4)||AgNO_(3)|Ag , the cell reaction is : Zn+2Ag^(+)rarr Zn^(2+)+2Ag. If E_("cell")^(@)=+0.36V , then calculate Delta^(@) for the cell reaction of that cell.

For a cell reaction involving two electron changes the standard emf of the cell is found to be 0.295V at 25C. The equilibrinm constant of the reaction at 25^@C will be?

The equilibrium constant of cell reaction : Ag_((s))+Fe^(3+)hArr Fe^(2+)+Ag^(+) is 0.335, at 25^(@)C . Calculate the standard emf of the cell Ag//Ag^(+), Fe^(3+), Fe^(2+)//Pt . Calculate E^(@) of Fe^(3+), Fe^(2+)//Pt half cell. (Given - E^@ of Ag^+//Ag = 0.8)

Consider the galvanic cell Cu|Cu^(2+)(0.13M)||Ag^(+)(0.01M)|Ag (i) Calculate the reduction potential of each electrode and EMF of the cell (ii) Is is reaction representing the cell spontaneous ? ["Given : "E_(Cu^(2+)|Cu)^(@)=+0.34V and E_(Ag^(+)|Ag)^(@)=+0.80V]

In a galvanic cell, the given cell - reaction takes place - Cd(s)+NiO_(2)(s)+2H_(2)O(l)rarr Cd (OH)_(2)(s)+Ni(OH)_(2)(s) The standard potentials of the half- cell reactions are - (1) Cd(OH)_(2)(s)+2e rarr Cd(s)+2OH^(-)(aq),E^(@)=-0.81V (2) NiO_(2)(s)+2H_(2)O(l)+2e rarr Ni(OH)_(2)(s)+2OH^(-)(aq), E^(@)=+0.50V . The standard potential of the cell is -

Calculate the emf of the cell. Zn|Zn^(2+)(0.001M)||Ag^(+)(0.1M)|Ag The standard potential of Ag//Ag^(+) half - cell is +0.80 V and Zn//Zn^(2+) is -0.76V.