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The equilibrium constant of cell reactio...

The equilibrium constant of cell reaction :
`Ag_((s))+Fe^(3+)hArr Fe^(2+)+Ag^(+)` is 0.335, at `25^(@)C`. Calculate the standard emf of the cell `Ag//Ag^(+), Fe^(3+), Fe^(2+)//Pt`. Calculate `E^(@)` of `Fe^(3+), Fe^(2+)//Pt` half cell.
`(Given - E^@ of Ag^+//Ag = 0.8)`

Text Solution

Verified by Experts

`E^(@)Fe^(3+)//Fe^(2+)=0.771V`
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