Home
Class 12
CHEMISTRY
Arrange the following in the increasing ...

Arrange the following in the increasing order of stability.
`CH_(3)CH_(2)CH=CH_(2), CH_(3)CH=CHCH_(3)(cis), CH_(3)CH=CHCH_(3)" (trans)"`

Text Solution

Verified by Experts

`CH_(3)CH_(2)CH=CH_(2) lt (CH_(3))CH=CH_(2)CH_(3)" (cis)" lt (CH_(3))_(2)C=CH_(2) lt CH_(3)CH=CHCH_(3)" (trans)"`
Promotional Banner

Topper's Solved these Questions

  • ISOMERISM IN ORGANIC CHEMISTRY

    NCERT BANGLISH|Exercise SELF EVALUATION (GEOMETRICAL ISOMERISM(Practice Question))|5 Videos

  • ISOMERISM IN ORGANIC CHEMISTRY

    NCERT BANGLISH|Exercise SELF EVALUATION (CONFORMATION)|2 Videos

  • ISOMERISM IN ORGANIC CHEMISTRY

    NCERT BANGLISH|Exercise SELF EVALUATION (CONFORMATION(Short answer questions.))|2 Videos

  • HYDROXY DERIVATIVES

    NCERT BANGLISH|Exercise Phenols|10 Videos

  • NUCLEAR CHEMISTRY

    NCERT BANGLISH|Exercise SELF EVALUATION|31 Videos

Similar Questions

Explore conceptually related problems

Arrange the following ions in order of increasing basicit :- CH_3CH_2, CH -= C, CH_2=CH

Arrange the following compounds in the increasing order of their acidic character. HC-=CH,CH_3OH,CH_3CH_3

Arrange the following compounds in increasing order of their boiling points- (a) (CH_(3))_(2)CH-CH_(2)Br (b) CH_(3)CH_(2)CH_(2)CH_(2)Br (c) (CH_(3))_(3)C-Br .

Arrange the following compounds in order of decreasing boiling point: CH_(3)CH_(2)CHBrCH_(3)(I), CH_(3)CH_(2)CH_(2)CH_(2)BR(II), (CH_3)_(3) CBr(III) .

Arrange the compounds in the order of increasing S_(N)1 reactivity: ClCH_(2)CH=CHCH_(2)CH_(3) (I), CH_(3)C Cl=CHCH_(2)CH_(3) (II) and CH_(3)CH = CHCH_(2)CH_(2)Cl (III)

The IUPAC name for CH_(3)CH_(2)CH_(2)CH(CH=CH_(2))CH_(2)CH_(2)CH_(3) is

Arrange the following in increasing order of reactivity towards nucleophilic addition. HCHO , CH_(3)CHO and CH_(3)COCH_(3)

Arrange in the order of increasing boiling point: (i) CH_(3)CH_(2)CH_(2)CH_(2)Br (ii) (CH_3)_(3)CBr (iii) (CH_3)_(2)CHCH_(2)Br

Arrange the following isomeric alkenes in order of increasing stability and give your reasons: (CH_(3))_(2)C=C(CH_(3))_(2)[I],CH_(2)=CHCH_(2)CH_(2)CH_(3)[II] CH_(3)CH=CHCH(CH_(3))(2)[III], CH_(3)CH=C(CH_(3))CH_(2)CH_(3)[IV]

Arrange in increasing priority: -CH_(2)CH_(3), -CD_(2)CH_(3), -CH_(3),-NH_(2), -NHCH_(3), -OH, -OCH_(3) .