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2 sin ^(2) "" (3pi)/(4) + 2 cos ^(2) "" ...

`2 sin ^(2) "" (3pi)/(4) + 2 cos ^(2) "" (pi)/( 4) + 2 sec ^(2) "" (pi)/(3) =10`

Answer

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Explore conceptually related problems

2 sin ^(2) "" (pi)/(6) + cosec ^(2) "" (7pi)/(6) cos ^(2) "" (pi)/(3) = 3/2

cos ((3pi)/( 4) + x) - cos((3pi)/( 4) -x) =- sqrt2 sin x

Knowledge Check

  • The value of (cos ^(2) ""(pi)/(12)+ cos^(2) ""(pi)/(4)+ cos ^(2) ""(5pi)/(12)) is-

    A
    `3/2`
    B
    `2/3`
    C
    `3/4`
    D
    `4/3`
  • Similar Questions

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    "tan"^(2)(pi)/(4) "sin"(pi)/(3) "tan"(pi)/(6) "tan"^(2)(pi)/(3) =

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