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21x^(2) - 28x + 10=0...

`21x^(2) - 28x + 10=0`

Text Solution

Verified by Experts

The correct Answer is:
`2/3 +- sqrt(14)/21 i`
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27x^(2) - 10x +1=0

Prove that the centres of the circles x^(2) + y^(2) - 10x + 9 = 0, x^(2) + y^(2) - 6x + 2y + 1 = 0 and x^(2) + y^(2) - 18x - 4y + 21 = 0 lie on a line, find the equation of the line on which they lie.

Knowledge Check

  • If k x^2 + 10 xy + 3 y^2 - 15x - 21y + 18 = 0 represents a pair of straight lines. Then the value of k is :

    A
    -3
    B
    3
    C
    4
    D
    -4

  • Two roots of the quadratic equation ix^(2) -10x -21i=0 is-

    A
    `7i,3i`
    B
    `-3i, 7i`
    C
    `3i,-7i`
    D
    `-3i, -7i`

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