Home
Class 9
PHYSICS
A man is 48m behind a bus which is at re...

A man is 48m behind a bus which is at rest. The bus starts accelerating at the rate of 1 m/`s^(2)`, at the same time the man starts running with uniform velocity of 10 m/s. What is the minimum time in which the man catches the bus? (8s)`(AS_(7))`

Promotional Banner

Topper's Solved these Questions

  • MOTION

    NCERT BANGLISH|Exercise LET US IMPROVE OUR LEARNING(MULTIPLE CHOICE QUESTION)|4 Videos

  • MOTION

    NCERT BANGLISH|Exercise THINK AND DISCUSS|14 Videos

  • MOTION

    NCERT BANGLISH|Exercise LET US IMPROVE OUR LEARNING(APPLICATION OF CONCEPTS)|7 Videos

  • MATTER AROUND US

    NCERT BANGLISH|Exercise Let us Improve our learning (Multiple choice questions)|3 Videos

  • REFRACTION OF LIGHT AT PLANE SURFACES

    NCERT BANGLISH|Exercise THINK AND DISCUSS|2 Videos

Similar Questions

Explore conceptually related problems

A man is 9 m behind a train at rest. The train starts with an acceleration of 2 "m.s"^(-2) and simultaneously the man starts running. He is able to board the train somehow after 3 s. Find the acceleration of the man.

A lift of mass 2000 kg is supported by thick steel ropes. If maximum upward acceleration of the lift be 1.2 m//s^(2) , and the breaking stress for the ropes be 2.8 xx 10^(8) N/ m^(2) , what should be the minimum diameter of the rope?

What is the force which produces an acceleration of 1 m//s^(2) in a body of mass 1 kg ?

A jet pIane starts from rest with an acceleration of 3 "m.s"^(-2) , and makes a run for 35 s before taking off. What is the minimum Iength of the runway and what is the velocity of the jet at take off?

The acceleration of a particle starting from rest moving in a straight line with uniform acceleration is 8m//sec^2 . The time taken by the particle to move the second metre is:

A car starting with velocity 10 "m.s"^(-1) attains an acceleration 1 "m.s"^(-2) . After what time interval will its velocity be 20 "m.s"^(-1) ?

A body is moving from rest with an acceleration a m . s^(-2) which is related to time t s by a = (3t +4) . What will be its velocity in time 2 s?

Two particles start moving from point A along a straight line AB at the same time in the same direction. One particle moves with a uniform velocity of 12 "m.s"^(-1) and the other with an acceleration of 2 "m.s"^(-2) and an initial velocity of 5 "m.s"^(-1) . After how much time will the two particles meet ?