What is the deceleration of a vehicle moving in a straight line that changes its velocity from 100 km/h to a dead stop in 10s?

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm//s^(2) , at time t seconds. If the velocity of the particel at time 2 seconds be 10cm/s, find its velocity at time t seconds.

Statement I : A particle moving with uniform acceleration has its displacement proportional to the square of time. Statement II : If the motion of a particle is represented by a straight line on the velocity -time graph its acceleration is uniform.

A scooter of mass 120 kg is moving with a uniform velocity of 108 km/h. the force requied to stop the vehicle in 10 s is

A particle is moving with a uniform acceleration along a straight line AB. Its velocity at A and B are 2 m/s and 14 m/s respectively. Then

A particle starts from the origin and moves along a straight line. If the velocity of the particle at time t seconds be 10t cm/s, find the distance traversed during first 4 seconds after the start.

A partiole is moving in a straight line such that its velocity at time t is proportional to t^(5) . Then its acceleration is proportional to

The law or motion of a body moving along a straight line is x=(1)/(2)vt, x being its distance from a fixed point on the line at time t and v is its velocity there. Then

A body of mass 10 kg is moving with a velocity of 100 m/s. find the force needed to stop it in 5 seconds.

A particle moves in a straight line and its velocity v (in cm/s ) at time t (in second ) is 6t^(2) - 2t^(3) , find its acceleration at the end of 4 seconds.

A charged particle moving in a straight line parallel to a uniform magnetic field enters the field. What will be its path in the field?